1143. Longest Common Subsequence
Medium
class Solution:
def longestCommonSubsequence(self, text1: str, text2: str) -> int:
n,m=len(text1),len(text2)
dp=[[0]*(m+1) for _ in range(n+1)]
for i, t1 in enumerate(text1):
for j, t2 in enumerate(text2):
if t1 == t2:
dp[i+1][j+1] = 1 + dp[i][j]
else:
dp[i+1][j+1] = max(dp[i+1][j] , dp[i][j+1])
return dp[-1][-1]
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